Math, asked by abcd7410, 9 months ago

please answer me this soon as possible ​

Attachments:

Answers

Answered by IamIronMan0
1

Answer:

Substitute values

 \frac{4}{3}  {( \sqrt{3}) }^{2}  + 3( \frac{ \sqrt{3} }{2} ) { }^{2}  - 2( \frac{2}{ \sqrt{3} } )  {}^{2} -  \frac{3}{4} ( \frac{1}{ \sqrt{3} } ) {}^{2}  \\  \\  = 4 +  \frac{9}{4}   -  \frac{8}{3}  -  \frac{1}{4}  \\  \\  =  \frac{48 + 27 - 32 - 3}{12}  \\  \\  =  \frac{40}{12}  \\  \\  =  \frac{10}{3}

Similar questions