Question

please answer me to the question (iii)&(vi)... please now

Answer 1

(iii) I have just modified image (iii) to solve it..
EGllABllDC( abcd is a rectangle)
FG=6
so, EF = AB - FG=15-6= 9 cm
EF is height of triangle abf and base is ad
so, area of triangle adf = 1/2 * EF * ad
= 1/2*9*30=135cm2
area of abcd= 30 * 15= 450 cm2
so, area of shaded part is 450-135=315cm2

(vi) diagram modified given above /\ ....
the measurements are in the image of the questions....
area of fae triangle is = 1/2*10*18= 90 cm2
area of abc triangle = 1/2*30*25= 375 cm2
area of cde triangle = 1/2*40*7= 140cm2
area of all unshaded triangle= 605 cm2
area of rectangle abcd = 1000cm2
so, area of shaded part is 395 cm2

if there is any problem please let me know in comment ....
leave a thanks and have a merry day
in the question diagram (vi)17 cm is wrong I had corrected it
------------------------------