Math, asked by samruddhipathak, 1 year ago

please answer me to this Question......
.
.
.

WITH PROPER STEPS
.
.please it's urgent.....​

Attachments:

Answers

Answered by AbhijithPrakash
1

_________________________________________

Hi,

This is AbhijithPrakash,

_________________________________________

The answer for your question is as Followed:

_________________________________________

Answer:

\frac{4}{3}

Step-by-step explanation:

sec 41° . sin 49 + cos 29° cosec 61° - 2/√3 ( tan 20°. tan 60 . tan 70) / 3(sin²31° + sin²59°)

⇒cosec (90°- 49°) . sin 49° + cos 29° sec (90° -29°) - 2/√3 (tan 20°. √3 . cot (90° - 20°)) / 3(sin²31° + cos²(90° - 31°))

⇒cosec 49° . sin 49° + cos 29° sec 29° - 2/√3 (tan 20° . √3 . cot 20°) /  3(sin²31° + cos²31°)

⇒1 + 1 - 2/√3 (1 . √3)) /  3(1) = 1 + 1 - 2/√3 (√3) /  3

⇒1 + 1 + 2 / 3 = 4/3

_________________________________________

Thanks,

Hope this Helps you,

Please mark it as Brainliest Answer....

_________________________________________


AbhijithPrakash: No If its wrong then it must be reported..
samruddhipathak: oo i am new so i don't konw about this
samruddhipathak: should i really report
AbhijithPrakash: of course
AbhijithPrakash: And Sorry for wrong answer...
samruddhipathak: it's ok...
AbhijithPrakash: The mistake was on the last step the sing was taken wrong by me..
AbhijithPrakash: *sign
samruddhipathak: ya i noticed it....
samruddhipathak: your answer mut be right if their was negative sign..
Answered by sneha9211376
3

Answer is 0

Hope it helps you..

Attachments:

samruddhipathak: thanks sia
samruddhipathak: sis
sneha9211376: Welcome
Similar questions