please answer me to this Question......
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WITH PROPER STEPS
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.please it's urgent.....
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Hi,
This is AbhijithPrakash,
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The answer for your question is as Followed:
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Answer:
Step-by-step explanation:
sec 41° . sin 49 + cos 29° cosec 61° - 2/√3 ( tan 20°. tan 60 . tan 70) / 3(sin²31° + sin²59°)
⇒cosec (90°- 49°) . sin 49° + cos 29° sec (90° -29°) - 2/√3 (tan 20°. √3 . cot (90° - 20°)) / 3(sin²31° + cos²(90° - 31°))
⇒cosec 49° . sin 49° + cos 29° sec 29° - 2/√3 (tan 20° . √3 . cot 20°) / 3(sin²31° + cos²31°)
⇒1 + 1 - 2/√3 (1 . √3)) / 3(1) = 1 + 1 - 2/√3 (√3) / 3
⇒1 + 1 + 2 / 3 = 4/3
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Thanks,
Hope this Helps you,
Please mark it as Brainliest Answer....
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AbhijithPrakash:
No If its wrong then it must be reported..
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