Question

please answer me urgently step by step explanation please clear image please answer send me ​

Answer 1

AnsWer:-

☞16

☞17

☞18

$\rule{200}{1}$

Explanation:–

➜Let the Numbers be:-

๛a,a+1,a-1

➜Their Sum=51

↝a+(a+1)+(a-1)=51

↝3a=51

↝a=$\frac{\cancel{51}}{\cancel{3}}$

↝a=17

↝a+1=17+1→18

↝a-1=17-1=16

$\rule{200}{2}$

Answer 2

Let 1st odd no. be x

then other 2 odd no.s will be - x+2&x+4

ATQ.

x+(x+2)+(x+4)=51

3x+6=51

3x=51-6=45

$x = \frac{45}{3}$

x=15

so, other 2 odd no.s are

x+2=17

x+4=19

Hence 3 consecutive odd numbers whose sum is 51 are

15,17,19

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