Question

please answer me urjnt

Answer 1

Answer:

3 units

Step-by-step explanation:

Let the value of x in both equations be 1.

3(1) - 4y - 7 = 0

3 - 4y = 7

y = 4/(-4)

y = -1 for equation 1

3(1) - 4y + 5 = 0

-4y = -5 - 3

y = -8/(-4) = 2 for equation 2

Therefore the coordinates are (1,-1) and (1,2).

Applying distance formula for these two,

Distance = [ (x1 - x2)^2 + (y1-y2)^2 ] ^-2

Distance = [ (1 - 1)^2 + (-1 -2)^2 ] ^ -2

Distance = [ (0) + (-3)^2 ] ^-2

Distance = 3 units