Question

please answer my circled question​

Answer 1

Answer:

☆ QUESTION ☆

4u^2 + 8U

FIND THE ZEROES

☆ ANSWER ☆

4U^2 + 8U

= 4U(U +2)

= (4U)(U +2)

THEREFORE ,

X = 1/4 AND X = -2

ZEROES OF 4U^2 +8U ARE 1/4 AND -2

HOPE IT HELPS

Answer 2

Answer:

the zeroes are 0 and -2

Step-by-step explanation:

4u^2+8u

=>4u(u+2)

It's possible if

4u=0 , u+2=0

=>u=0 , =>u=-2

now,

0+(-2)= -2

= -8/4

=-b/a

0×(-2)=0

=0/4

=c/a