Question

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Answer 1

Explanation:

A is Carbonate ore and B is Sulphide ore

1) On Calcinating ACO₃

ACO₃ -----> AO + CO₂

Using Zn as reducing agent:

AO + Zn ----> A + ZnO

Thus metal A is obtained

2) On roasting BS

2BS + 3O₂ -----> 2BO + 2SO₂

Using Zn as reducing agent:

BO + Zn ----> B + ZnO

Thus metal B is obtained

Answer 2

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