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Answer:
We need ∫logxdx
It can be done by using integration by parts,
i.e., ∫udv=uv−∫vdu
By ILATE, log function should have more priority than algebraic function,
So, u=logx,
dv=dx⇒v=x
So, ∫logxdx=logx.(x)−∫x.(logx)′
⇒xlogx−∫x.1xdx
⇒xlogx−∫dx
⇒xlogx−x+C
∴∫logxdx=xlogx−x+C
Where C is the integration constant.
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