Question

please answer my question ​

Answer 1

hey mate

note:answer attachment

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@abhi.

Answer 2

Hello again friend

Given:

√3 sin theta=cos theta

=>(sin theta)/(cos theta)=1/√3

=>tan theta=tan30°

Therefore,

theta=30°----(1)

Now,

Value of sin theta.tan theta (1+cot theta)/sin theta + cos theta

=[sin30°tan30°(1+cot30°)]/(sin30°+cos30°)

=[(1/2)(1/√3)(1+√3)]/[1/2+√3/2]

=[1/(2√3)(1+√3)]/[(1+√3)/2]

After cancellation,we get

Required value=1/√3

Hope helps

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