Physics, asked by mpjawandhiya, 10 months ago

please answer my question ​

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Answered by IamIronMan0
1

Answer:

A

Explanation:

Let equivalent resistance be x then equivalent is also x

x = r + r +  \frac{rx}{r + x}  \\ x(r + x) = 2r(r + x) + rx \\  {x}^{2}  - 2rx - 2 {r}^{2}  = 0 \\ x =  \frac{2r \pm \:  \sqrt{ {4r}^{2}  + 8 {r}^{2} } }{2}  = r( \sqrt{3}  + 1)

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