Math, asked by nikita123466, 11 months ago

please answer my question ​

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Answered by Ritu012
0

Answer:

a^-1=1/a

( \frac{1}{4}  -  \frac{1}{5} ) ^{2}  \times  (\frac{5}{8} )  ^{ - 1}  \\  (\frac{5 - 4}{20} ) ^{2}  \times  \frac{8}{5}  \\  \frac{1}{20 ^{2} }  \times  \frac{8}{5}  \\  \frac{1}{250}

hope this will help you

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