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Let father's present age be y, son's present age be x and age difference be n
After n years son's age= x+n and father's age= y+n
(x+n)+(y+n)= 126
y-x= n
y= x+n
(x+n)+((x+n)+n)= 126
1) 2x+3n= 126
Before n years son's age= x-n and father's age= y-n
(x-n)+(y-n)= 38
(x-n)+((x+n)-n)=38
2) 2x-n=38
Solving eqn 1) and 2),
n=22
x=30
y=x+n=22+30=52
#BAL #answerwithquality
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