Math, asked by shashank4212, 10 months ago

please answer my question​

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Answered by Siddharta7
1

Answer:

1

Step-by-step explanation:

Given,

x + y + z =9

Square on both sides, we get

=> (x^2 + y^2 + z^2 + yz + xz + yz  + xy + xz + xy ) = 81

=> x^2 + y^2 + z^2 + 2xy + 2yz + 2xz = 81

=> (x^2 + y^2 + z^2)  + 2 ( xy + yz + xz) = 81

=> (x^2 + y^2 + z^2)  + 2 ( 40) = 81

=> (x^2 + y^2 + z^2) = 81 - 80

=> (x^2 + y^2 + z^2) = 1

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