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Let the length of shortest side = x cm
Hypotenuse=(12+x) cm
Other side = 12+x -6=(6+x) cm
Therefore by pythogoras theorem,
(Hypotenuse)^2=(Shortest side )^2+(Other side)^2
(12+x)^2=x^2+(6+x)^2
144+x^2+24x=x^2+36+x^2+12x
144-36=2x^2+12x-x^2-24x
108=x^2-12x
x^2-12x-108=0
x^2-18x+6x-108=0
x(x-18)+6(x-18)=0
(x-18)(x+6)=0
x=18 or x=-6
Since x is side which can't be negative.
Therefore , x=18cm
Length of shortest side =18cm
Length of Hypotenuse = 30cm
Length of Other side = 24 cm
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Answer:
x = 18 so shortest side is 18. hypotenuse = 12 + 18 = 30
and third side = 6 + 18 = 24
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