Question

please answer my question​

Answer 1

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QUESTION -

The sum of a two digit number and the number obtained by reversing the digits is 121.

Find the number if it's unit place digit is 5.

SOLUTION -

From the above Question, we can obtain the following information....

The sum of a two digit number and the number obtained by reversing the digits is 121.

it's unit place digit is 5.

Let the number be X 5

So,

Reversed Number : 5X

Sum of numbers

=> 10x + 5 + 50 + x = 121

=> 11x + 55 = 121

=> x + 5 = 11

=> x = 6

Thus the original number becomes 65 .

ANSWER :

the original number becomes 65 .

Answer 2

Answer:

No. is 65

Step-by-step explanation:

Hi,

TENS DIGIT = Y, ONES DIGIT = X

(10Y + X) + (10X+Y) = 121

10Y +5 + 50 + Y = 121

11Y + 55 = 121

11Y = 121 - 55

11Y = 66

Y = 66/11

Y = 6

10y + x = 60 + 5 = 65

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