please answer my question
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When a simple pendulum makes 10 oscillations in 20 seconds, the time taken for each oscillation = 20/10 = 2 seconds. Hence, as the time period is calculated to be 2 seconds, the frequency of oscillation = 1/T = 1/ 2 = 0.5 Hertz. Therefore, the frequency of that pendulum is found to be 0.5 Hz.
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Answered by
1
Answer: Number of oscillations= 10
Time taken = 20 seconds
Time period = time taken/ number of oscillations
= 20/10
= 2 seconds
Frequency of its oscillations = 1/time period
= 1/2
= 0.5 Hertz
Therefore, the time period = 2 seconds and the frequency = 0.5 Hertz.
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