Question

Please answer my question

Answer 1

Answer:

answer is 11/9

hope it helps you

thanku

Answer 2

${\huge{\bold{\purple{\bigstar{\boxed{\boxed{\bf{Question}}}}}}}}$

solve

$\sf\dfrac{x}{6} + \dfrac{121}{110} = \dfrac{110}{99}$

${\huge{\bold{\purple{\bigstar{\boxed{\boxed{\bf{Solution}}}}}}}}$

$\sf\dfrac{x}{6} + \dfrac{121}{110} = \dfrac{110}{99}$

$\sf\dfrac{x}{6} = \dfrac{110}{99}-\dfrac{121}{110}$

$\sf\dfrac{x}{6} = \dfrac{110\times 10 - 121\times 9}{990}$

$\sf\dfrac{x}{6} = \dfrac{1100-1089}{990}$

$\sf\dfrac{x}{6} = \dfrac{21}{990}$

$\sf\dfrac{x}{6} = \dfrac{\cancel 21}{\cancel 990}$

$\sf\dfrac{x}{6} = \dfrac{7}{330}$

$\sf{x} = \dfrac{7\times \cancel 6 }{\cancel 330}$

$\sf{x} = \dfrac{7}{55}$

${\bold{\blue{\boxed{\bf{\dag x = \dfrac{7}{55} }}}}}$

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