Please answer my question
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a and b are supplementary angles.
Therefore,
b+a=180 degrees
b-a=80 degrees
b+a-(b-a)=180-80
a=50 degrees
b=180-50
b=130 degrees
Therefore,
b+a=180 degrees
b-a=80 degrees
b+a-(b-a)=180-80
a=50 degrees
b=180-50
b=130 degrees
Answered by
1
Step-by-step explanation: Hello !, hope this may help u,
It's given that AOB is a line,
so ∠a+∠b = 180°
also, ∠b-∠a=80°
∠b= 80+ ∠a.
By substituting the value of ∠b in the first equation, we get,
∠a+80+∠a = 180
2∠a = 180-80
2∠a =100
∠a = 100/2
∠a = 50°
therefore, ∠b =80 +∠a
= 80+50 = 130°.
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