Question

please answer my question​

Answer 1

Answer:

(4a² - 3ab)

Step-by-step explanation:

sum of (a² + 4b² - 6ab) and (a² - b² + 2ab):

(a² + 4b² - 6ab) + (a² - b² + 2ab)

= a² + 4b² - 6ab + a² - b² + 2ab

= a² + a² + 4b² - b² - 6ab + 2ab

= 2a² + 3b² - 4ab.

Subtracting (-2a² + 3b² - ab) from (2a² + 3b² - 4ab):

(2a² + 3b² - 4ab) - (-2a² + 3b² - ab)

= 2a² + 3b² - 4ab + 2a² - 3b² + ab

= 2a² + 2a² + 3b² - 3b² - 4ab + ab

= 4a² - 3ab.

Answer 2

Answer:

Please see the image below :)