Question

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Answer 1

Answer:

In the adjoining figure, the tension in the string connecting A and B is ca 59 - T: 50 LUULL T - 39 = 3 ZA T' g = a Al3 kg] [5 kec D) 10€ B 1 kg A constant force F=m,g/2 is applied on the block of mass m, as shown in.

Answer 2

Answer:

10g/9

• finding the acceleration: a= (5g-4g)/9 = g/9

• T AB -1g =1 x g/9

• T AB = 10g/9

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