Question

please answer my question​

Answer 1

Answer:

Given -:

The line n is transversal to the line l and m in the given figure. Find the unknown angles. If angle 2 = 40°.

Solution -:

Angle 2 = 40°.

Angle 4 = 40° (Vertically opposite angles)

Angle 1 + 40° = 180° (Linear pair)

Angle 1 = 180° - 40°

Angle 1 = 140°.

Angle 3 = 140° (Vertically opposite angles).

Angle 5 + Angle 4 = 180° (Co-interior angles)

Angle 5 + 40° = 180°

Angle 5 = 180° - 40°

Angle 5 = 140°.

Angle 7 = 140° (Vertically opposite angles)

Angle 8 + Angle 5 = 180° (Linear pair)

Angle 8 + 140° = 180°

Angle 8 = 180° - 140°

Angle 8 = 40°.

Angle 6 = 40° (Vertically opposite angles)

Hence, we get -:

Angle 1 = 140°.

Angle 2 = 40°.

Angle 3 = 140°.

Angle 4 = 40°.

Angle 5 = 140°.

Angle 6 = 40°.

Angle 7 = 140°.

Angle 8 = 40°.

Hope you understood the sum and it cleared your doubt! :)