please answer my question
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Let denominator be x
Now, Numerator is x-6
A.T.Q
X-6±3/x is equal to 2/3
x-3/x is equal to 2/3
Aftr that u can solve
Now, Numerator is x-6
A.T.Q
X-6±3/x is equal to 2/3
x-3/x is equal to 2/3
Aftr that u can solve
GeniusTrippan:
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Answered by
2
let the denominator be x.
Therefore, A/Q,
fraction = (x-6)/x.
Now,
numerator= x-6+3= x-3
new fraction = (x-3)/x= 2/3
therefore, x=9....(after cross multiplication)
hence original fraction =( x-6)/x = 3/9 =1/3
Therefore, A/Q,
fraction = (x-6)/x.
Now,
numerator= x-6+3= x-3
new fraction = (x-3)/x= 2/3
therefore, x=9....(after cross multiplication)
hence original fraction =( x-6)/x = 3/9 =1/3
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