Math, asked by nikhilkumar4, 1 year ago

please answer my question

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Answered by shanujindal48p68s3s
1

2560 = 5 \times  {2}^{9}
For a number to be a perfect cube, the powers of the prime numbers in its prime factorisation must be multiples of 3.
So, we have to make 5 to 5^3.
Thus we need to multiply it by 5^2=25.
 {2}^{9}  \times 5 \times  {5}^{2}  \\  =  {2}^{9}  \times  {5}^{3}  \\  =  {( {2}^{3} \times 5) }^{3}  \\  =  {40}^{3}
Answered by sijasubbiah
0
Hey

Here is your answer,

2 l 2560
2 l 1280
2 l 640
2 l 320
2 l 160
2 l 80
2 l 40
2 l 20
2 l 10
5 l 5
l 1

5 is only single
so, we multiply by 25
then, it is a perfect cube.

Hope it helps you!

Mark it as brainlist.

nikhilkumar4: wlc
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