Question

PLEASE ANSWER MY QUESTION.

Answer 1

Let two sides which are equal in an isosceles trianlge be x

and other given as 16 cm base

then

perimeter = x + x + 16

36 = 2x + 16

2x = 36 - 16

2x = 20

x = 10

here we have all the sides
e.i.,

a = 10

b = 10

c = 16

$let \: s \: = semipermeter \: = \frac{perimeter}{2} \\ \\ = \frac{36}{2} \\ \\ = {18} \\ \\ \\ \\ (s - a) = 18 - 10 = 8 \\ (s - b) = 18 - 10 = 8\\ ( s- c) = 18 - 16 = 2\\ \\ \\ \\ \\ using \: herons \: formulae \\ \\ area \: of \: triange \\ \\ = \sqrt{s(s - a)(s - b)(s - c)} \\ \\ = \sqrt{18 \times 8 \times 8 \times 2} \\ \\ = \sqrt{ {3}^{2} \times {2}^{2} \times {2}^{2} \times {2}^{2} \times {2}^{2} } \\ \\ = 3 \times 2 \times 2 \times 2 \times 2\\ \\ = 48 \: {cm}^{2}$