Question

please answer my question ​

Answer 1

AM=21 CM

BM=10 CM

Step by step

→ Area AAMD: Area AAMC 42: 14:3:1 =

(1/2)* AM * MD * sin e: (1/2)* MC * MD sin (180 - 0) = 3:1 *

→ AM * sin 0: MC * sin = 3:1

➡AM: MC = 3:1

→ AM/MC = 3/1

→ AM/7 = 3/1

→ AM = 21 cm (Ans.)

similarly,

→ Area AMB: Area CMB = AM : CM

→ Area AMB : 28 = 21:7

→ Area AMB / 28 = 3/1

➡ Area AMB = 28 * 3

→ Area AMB = 84 cm².

similarly,

➡ Area DMC: Area BMC = DM: BM

➡ 14:28 = 5: BM

➡ (1/2) = 5/BM

→ BM = 10 cm (Ans.)

Conclusion :- Ratio of areas of A's lies on either side of a straight line is equal to ratio of their base.