Question

please answer my question​

Answer 1

Answer:

Answer is the"12-¹" (4-¹×3-¹)+12-¹=12-¹.

Answer 2

$( {4}^{ - 1} \times {3}^{ - 1} ) \div {12}^{ - 1}$

$= {(4 \times 3)}^{ - 1} \div {12}^{ - 1}$

$= {12}^{ - 1} \div {12}^{ - 1}$

$= {12}^{ (- 1 )- ( - 1)}$

$= {12}^{ - 1 + 1}$

$= {12}^{0}$

$= 1$