Math, asked by dhruvalt03, 2 days ago

please answer my question ​

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Answered by bagkakali
0

Answer:

66(y^4-5y^3-24y^2)÷6y(y-8)

=66y^2(y^2-5y-24)÷6y(y-8)

=66y^2(y^2-8y+3y-24)÷6y(y-8)

=66y^2{y(y-8)+3(y-8)}÷6y(y-8)

=66y^2(y-8)(y+3)÷6y(y-8)

=66y^2(y-8)(y+3)/6y(y-8)

=11y(y+3)

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