Question

please answer my question​

Answer 1

Answer:

Step-by-step explanation:

Let the numbers be "x", " x+2"

Given,

x+x+2, 136

2x + 2 = 136

2x = 134.

x = 67.

The consecutive numbers are 67, 69.

7. Given Question,

The sum of three consecutive odd numbers is 213. Find the numbers.

Now,

We know that consecutive odd numbers have a difference of 2, like in, 3, 5, 7

and 9.

So, we can infer that all consecutive odd numbers have a difference of 2.

Then,

If we take one number to be "x", Then,

The other two numbers will be "x + 2" and "x + 4".

So.

=>(x) + (x+2)+(x+4)=213

=>X+X+2+x+4=213

=> 3x + 6 = 213

On transposing 6 from LHS to RHS, we get :

=> 3x = 213-6

=> 3x = 207

On transposing 3 from LHS to RHS, we get :

=> x = 207/3

=> x = 69

Now, we have got one number to be 69.

So, the other numbers will be :

(69+2) = and (69 +4)= 73

Therefore, the numbers are 69, 71 and 73 when the sum of three consecutive odd numbers is 213.

9. Let three consecutive even no. be x+2, x, x-2

∴ x+2 + x + x-2 =504

3x = 504

X = 504/3 = 168

∴x= 8

∴x+2 = 168+2 = 170

∴x-2 = 168-2 = 166

The three consecutive no. are 166,168,170