please answer my question
Attachments:
Answers
Answered by
0
cosA/(1-tanA) - sin²A/(cosA-sinA)
= cosA/(1-sinA/cosA) - sin²A/(cosA-sinA)
= cos²A/(cosA-sinA) - sin²A/(cosA-sinA)
=(cos²A-sin²A)/(cosA-sinA)
=(cosA-sinA)*(cosA+sinA)/(cosA-sinA) (using identity a²-b²=(a-b)*(a+b))
=(cosA+sinA)
yadavyash13:
I don't understand
Similar questions
Math,
7 months ago
English,
7 months ago
Math,
1 year ago
Environmental Sciences,
1 year ago
Science,
1 year ago
Computer Science,
1 year ago