Question

Please answer my Question

Answer 1

⏩hey there hang on❕❕, here's ur answer

⏩ given⏹ sum of perimeter of two squares is given by

➖ A1+A2= 4r1+4r2= 4(r1+r2)==(1)

sum of their area is given by
P1+ P2= r1^2+r2^2==(2)

let the side be x of the first square (r1) , then

first equation will be

=. 4(x+r2)= 41

=. 4x+r2= 41

r2= 41-4x===(3)

from equation 2 we have



36= x^2+ r2

r2= 36- x^2===(4)

equating 3 and 4

41-4x= 36-x^2

41-36= 4x-x^2

5= 4x-x^2

x^2-4x+5=0

then factorising it we get

x^2-5x+x-5=0

x(x-5)+1(x-5)=0
(x-5)(x+1)=0

x-5=0
x=5===(5)

x+1=0

x=-1==(6)

we get confused by two values , but we know that distance cant be negative , hence equation 5 is taken

x= 5 the side of the first square


then substituting the value in equation 3 or 4


, lets take 3

THEN we get

r2= 41-4x = 41- 4(5) = 41- 20= 21 cm

r2= 21cm the side of the second square...



✌✌hope so buddy it helps u ❕❕

(thanks for regaining the gained thing)

##be brainly

Answer 2

here is the sollution of your question
sorry for bad handwriting