Question

please answer my question

Answer 1

To the extreme right,

2,3 and 5Ω are in series.

So Reff = 10Ω

This 10Ω is parallel to the other 10Ω

So Rp = 10/2 = 5Ω

This 5Ω is in series with 5 and 2Ω

So Rs = 5+2+5 = 12Ω

Answer 2

Find the resistance of 2Ω , 3Ω , 5Ω

They are in series .

Hence : R = 2Ω + 3Ω + 5Ω

                 = 5Ω + 5Ω

                 = 10Ω

Find the resistance between R and 10Ω

They are in parallel .

Hence : 1 / R = 1 / 10Ω + 1 / 10Ω

==> 1 / R = 2 / 10 Ω

==> 1 / R = 1 / 5 Ω

==> R = 5 Ω

Find the resistance between this R , 2Ω and 5Ω

They are in series.

Hence resistance = 5 Ω + 2 Ω + 5 Ω

                              = 12 Ω

The equivalent resistance is 12 Ω

Hope it helps !

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