Question

please answer my question​

Answer 1

Let the consecutive terms of the ap be : a-d, a , a+d

Now,

a+a-d+a+d=30

3a = 30

a = 10

And

(a-d)a(a+d)=360

Putting the value of a

(10-d)10(10+d)=360

(100-d²)10=360

100-d²=36

d²=100-36

d²=64

d=8

Now the aps terms are

2,10,18(@NSWER)

HOPE IT HELPS