please answer my question as soon as possible exam in 2 hrs
Attachments:
Aashitaaaa:
...
Answers
Answered by
3
Hope it helps friend and mark as brainelist,i have helped you so much please mark as brainelist
In the triangle PQR,
PQ+PR>QR(Sum of any two sides of triangle is grater than its third side)
And QR=SQ+SR
Therefore,PQ+PR>SQ+SR
Hence,SQ+SR<PQ+PR
Hence,proved
In the triangle PQR,
PQ+PR>QR(Sum of any two sides of triangle is grater than its third side)
And QR=SQ+SR
Therefore,PQ+PR>SQ+SR
Hence,SQ+SR<PQ+PR
Hence,proved
thank u so much
Similar questions