Please answer my question for POINTS!!!!
A wooden block floats in alcohol with 3/8 th of its length above alcohol. If it is made to float in water, what fraction of its length is above watet ?
(Density of alcohol is 0.80 g/cm³)
Answers
Answered by
1
I'm not going to do the whole thing ,I'm telling you the logic
supposing the block has a uniform base are A
and length L, the volume of alcohol displaced =
AL*3/8
then buoyant force is ( vol displaced) * density of liquid * g
when you will dip it in water then also inorder for the block to float it has to have same buyont force
hence buyont force in water = buyont force in alcohol
Ax( density of water ) * g = AL*3/8 *( density of alcohol) *g
x = L*3/8 * 0.8
x= L*3/10
supposing the block has a uniform base are A
and length L, the volume of alcohol displaced =
AL*3/8
then buoyant force is ( vol displaced) * density of liquid * g
when you will dip it in water then also inorder for the block to float it has to have same buyont force
hence buyont force in water = buyont force in alcohol
Ax( density of water ) * g = AL*3/8 *( density of alcohol) *g
x = L*3/8 * 0.8
x= L*3/10
Similar questions