please answer my question. I will give you the brainliest answer
Q. (a) in a chocolate the ratio of the masses of cocoa:milk:other ingredient is 3:2:5.
1. What fraction of the chocolate is cocoa?
2.the mass of a chocolate is 28g. Calculate the mass of milk in a chocolate.
(b) the chocolates were sold in boxes. In 1996,each box cost $4.80. Fiona had $29 and bought as many boxes as possible.
1. How many boxes did she buy?
2.how much money did she have left?
(c) The price in 1998 was 10% more than the 1996 price of $4.80. Calculate the price in 1998.
(d) The price of $4.80 was an increase of 20% on the price of 1990. Calculate the price in 1990.
Answers
Answered by
0
take x as common multiple
Anonymous:
pls answer my question with steps for part a b c and d
Answered by
5
a) 1. The cocoa is 3/10 parts of the chocolate
2. Let all ingredients be x
3x + 2x + 5x = 10x = 28g
Milk is 2x/ 10x
So,

b)1.No of boxes she bought = Money she had ÷cost of one box
=29÷ 4.8
=6.04
So she bought 6 boxes
2. The change she had was $0.20
29 - (4.8 × 6) = 0.20 dollars
c) Price in 1998 was $5.28
[(10/100) × 4.80] + 4.80 dollars
= $5.28
d)Price in 1990 was $5.76
[(20/100) × 4.80] + 4.80 dollars
= $5.76
Hope this helps you!!!!
Please mark this as the Brainliest
2. Let all ingredients be x
3x + 2x + 5x = 10x = 28g
Milk is 2x/ 10x
So,
b)1.No of boxes she bought = Money she had ÷cost of one box
=29÷ 4.8
=6.04
So she bought 6 boxes
2. The change she had was $0.20
29 - (4.8 × 6) = 0.20 dollars
c) Price in 1998 was $5.28
[(10/100) × 4.80] + 4.80 dollars
= $5.28
d)Price in 1990 was $5.76
[(20/100) × 4.80] + 4.80 dollars
= $5.76
Hope this helps you!!!!
Please mark this as the Brainliest
Similar questions
Art,
9 months ago
Computer Science,
9 months ago
Social Sciences,
9 months ago
Social Sciences,
1 year ago
Math,
1 year ago