Math, asked by ramaramachandra87, 5 hours ago

Please answer my question.
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Answered by XxMrZombiexX
120

Question :

  • sahait deposited a sum of ₹8000 at compound interest in the bank at the rate of 18% per annum, fir 3 years .What interest will he get after the end of 3 years ?

 \qquad \qquad  \underline{ \red{\rule{100mm}{2mm}}}

 \green{\begin{gathered}\frak{Given \;that}\begin{cases}\sf{\:\; \:Principle \:  \: ( P ) = \bf{Rs\;8000}}\\\sf{ \: \: \:Rate \:  of  \: interest  \: (R ) = \bf{18\%\;}}\\\sf{ \: \: \:Time \:  \:  (T)= \bf{3 \: years}}\end{cases}\end{gathered}   }

  \:  \:  \:  \:  \:  \:  \underline {\underline{ \blue{ \large \: \frak{Neeed\; to\; find \;out  :  -  - }}}}

  • What interest he get after 3 years ?

 \orange{ \qquad \large \sf \underline{\underline{ Solution \ \: :  -  -  }}}

Using compound interest formula

 \pink{ \longmapsto \fbox{ \boxed{ \bf \: A=P   \bigg\lgroup1 + \frac{r}{100}  \bigg \rgroup^{t} }}}

Where,

  • A = amount
  • P = principal
  • r = rate of interest
  • t = time (in years)

 \large \underline{ \bf \: putting \: values \: we \: get \: }

 \longmapsto { \bf \: A=P   \bigg\lgroup1 + \frac{r}{100}  \bigg \rgroup^{t} } \\  \\

 \\   \tt\longmapsto \: A = 8000 \bigg \lgroup 1 + \frac{18}{100}  \bigg \rgroup^{3} \\  \\

 \\   \tt\longmapsto \: A = 8000 \bigg \lgroup  \frac{100 + 18}{100}  \bigg \rgroup^{3}  \\  \\

 \\   \tt\longmapsto \: A = 8000 \bigg \lgroup  \frac{118}{100}  \bigg \rgroup^{3}  \\  \\

 \\   \tt\longmapsto \: A = 8000 \times  \frac{118}{100}  \times  \frac{118}{100}  \times  \frac{118}{100}  \\  \\

 \\   \tt\longmapsto \: A = 8 \cancel0 \cancel{00 }\times  \frac{118}{1 \cancel{00}}  \times  \frac{118}{10 \cancel0}  \times  \frac{118}{100}  \\  \\

 \\  \tt\longmapsto \: A =  \: 8 \times  \frac{118}{1}  \times  \frac{118}{10}  \times  \frac{118}{100}  \\  \\

  \\  \tt\longmapsto \: A =  \frac{13144256}{1000}  \\  \\

 \\ \large   \pink{\tt\longmapsto \: A =  13144.256}\\  \\

 \large \bf \: interest \: he \: will \: get \: after \: the \: end \: of \: 3 \:years \:

 \longmapsto \:  \pink{ \fbox{ \boxed{Total Amount - Principal amount }}}

 \\  \\  \longmapsto \bf \: 13144.256 - 8000 \\  \\  \\ \frak{  \longmapsto5144.256}

 \bigstar  \fbox{\boxed{ \orange{ \sf \: Therfore \:  he  \: will \:  get \:  interest  \: after  \: 3 \:  years = Rs. 5144.256}}} \bigstar

 \underline{\rule{100mm}{2mm}}

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