Question

Please answer my question.
(If you do not give the correct answer, I will report your answer)​

Answer 1

Explanation:

1) The following figure shows the journey of a car from A to C through B .

a) What is the distance travelled by the car?

Distance travelled is total distance covered by the car. So,

$\dashrightarrow \quad \rm { Distance \; Travelled = AB + BC}$

$\dashrightarrow \quad \rm { Distance \; Travelled = (60 + 80) \; m}$

$\dashrightarrow \quad \underline{\boxed{\bf { Distance \; Travelled = 140 \; m}}}$

b) What is the displacement ?

Displacement is the shortest distance from initial to the final position of the body. The shortest distance between to positions is always a straight line.

Here, initial position is A and final position is C. So, the shortest distance can be find by joining A and C with a straight line, AC.

$\dashrightarrow \quad \underline{\boxed{\bf { Displacement = 130 \; m \; (from \; A \; to\; C)}}}$

$\rule{200}2$

ii) The following figure shows the journey of a cyclist from P to R through Q.

a) What is the distance travelled by the cyclist?

Distance travelled is total distance covered by the car. So,

$\dashrightarrow \quad \rm { Distance \; Travelled = PQ + QR}$

$\dashrightarrow \quad \rm { Distance \; Travelled = (40 + 50) \; m}$

$\dashrightarrow \quad \underline{\boxed{\bf { Distance \; Travelled = 90 \; m}}}$

b) What is the displacement ?

Displacement is the shortest distance from initial to the final position of the body. The shortest distance between to positions is always a straight line.

Here, initial position is P and final position is R. So, the shortest distance can be find by joining P and R with a straight line, PR.

$\dashrightarrow \quad \rm { Displacement = PR}$

$\dashrightarrow \quad \rm { Displacement = PQ + QR}$

$\dashrightarrow \quad \rm { Displacement =(40 + 50) \; m }$

$\dashrightarrow \quad \underline{\boxed{\bf { Displacement = 90 \; m (from \; P\; to\; R)}}}$

c) Find the situation in which the magnitude of of distance and displacement becomes equal.

$\longmapsto$ If a body travels in a straight line in a single direction, then the magnitude of of distance and displacement becomes equal. The same thing has happened in this part of the question, the body travels in a straight line in a single direction, so the magnitude of of distance and displacement becomes equal, that is 90 m.

Answer 2

Answer:

I) a) Distance = length of original path = AB + BC = 60 m + 80 m = 140 m

b) Displacement = shortest length b/w initial point and final one = AC = 130 m

II) a) Distance = length of original path = PQ + QR = 40 m + 30 m = 70 m

b) Diplacement = shortest length b/w P and R = 70 m

c) When a particle travels in a straight path, it's magnitude of distance is same of that of displacement.