please answer my question immediately!!
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angle acp is 50(straight line angle) angle abc is 30 (given) then bac is 180-(50+30) that is 100
angle acp is 50(straight line angle) angle abc is 30 (given) then bac is 180-(50+30) that is 100
Nakshu1:
its not the right answer
to my question
Its Right
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for the first one
In Triangle ABC, angle B= 30° and angle angle ACD=110°
So, angle BCA= 180°-110° (linear pair)
Angle BCA = 70°
Hence angle A = 180° - (70°+30°) (Angle Sum Property)
So, angle A = 180° - 100°
angle A = 80°
In Triangle ABC, angle B= 30° and angle angle ACD=110°
So, angle BCA= 180°-110° (linear pair)
Angle BCA = 70°
Hence angle A = 180° - (70°+30°) (Angle Sum Property)
So, angle A = 180° - 100°
angle A = 80°
thanks
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