please answer my question .In the given figure,DE//BC.if AD=4cm and DB=2cm,
find area of ABC if area of ADE=16cm^2.
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As DE || BC, and angle A is common,
triangle ADE ~ triangle ABC.
AE = 8 cm, EC = 2 cm, AC = 8 + 2 = 10 cm
As the both triangles are similar,
Ratios of their respective sides are equal.
AE / AC = DE / BC
8 / 10 = DE / 6
DE = 48 / 10 = 4.8 cm
DE = 4.8 cm
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