Question

please answer my question it is urgent
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Answer 1

Answer: your question is

$5^{(2x - 1)}   = \frac{1}{(125)^{(x-3)}} \\5^{(2x - 1)}   = \frac{1}{(5)^{3(x-3)}} \\\\5^{(2x - 1)}   = \frac{1}{(5)^{(3x-9)}} \\\\\\2x - 1 = -3x + 9\\\\5x = 10\\\\x = 2$

:. Base is equal so, exponent will be equal

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation: