Question

please answer my question it's urgent​

Answer 1

Answer:

bhen urgent answer koi nahi deta

Answer 2

Step-by-step explanation:

a/b=b/c=c/a

This implies that:

b²=ac

c²=ab

a²=bc

Given equation:

a/a+2b=a-2b/a-4c

Consider LHS of this equation,we get

a/a+2b

On multiplying numerator and denominator by

(a-2b) we get

a(a-2b)/(a+2b)(a-2b)

a(a-2b)/a²-4b²)

Put b²=ac

a(a-2b)/(a²-4ac)

a-2b/a-4c

Which is equal to RHS

Therefore,

LHS=RHS

HENCE PROVED