Question

please answer my question it's urgent​

Answer 1

Answer:

Step-by-step explanation:

Let f(x)=k²x³-kx-1

x-1 is factor of f(x)

then x-1=0

x=1

so f(1)=0

So k²(1)³-k(1)-1=0

k²-k-1=0

k=(-1±√1+4)/2

=(-1±√5)/2