Question

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Answer 1

Answer:

24abc

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Answer 2

Answer:

(2ab+3c)^2 -(2ab-3c)^2

(2ab+3c)^2. = (a+b)^2. a^2+b^2+2ab

-(2ab-3c)^2. =(a-b)^2. a^2+b^2-2ab

(2ab+3c)^2

=2ab^2+3c^2+2(2ab)(3c)

=2ab^2+3c^2+12abc. (i)

then

-(2ab-3c)^2

-(2ab^2-3c^2-2(2ab)(-3c)

-(2ab^2+(-3c^2)+12abc)

-2ab^+3c^2+12abc. (ii)

now put these two equation

2ab^2+3c^2+12abc

-2ab^2+3c^2+12abc

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0. 3c^2+12abc

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Step-by-step explanation:

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