Question

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Answer 1

Answer:

Given, length of the room (l) = 4.5 m

Breadth of the room (b) = 3m

Height of the room (h) = 350 cm = 3.5 m

And the cost of plastering = Rs. 8perm²

Therefore, the area of the walls = 2h(l+b)

= 2×3.5×(4.5+3) = 7×(7.5) = 52.2 m²

Area of the ceiling = lb = 4.5×3 = 13.5m²

Area of the room = 52.5+13.5 = 66m²

Hence, the cost of plastering = 66×8

= Rs.528

Answer 2

Solution,

→ Measures given

Length = 4.5 m

Breadth = 3 m

Height = 350 cm = 3.5 m

→ Area of room to be plastered

= LSA + area of ceiling

= 2 (lh + bh) + lb

= 2 [(4.5x3.5) + (3x3.5)] + (4.5x3)

= 2 x [15.75 + 10.5] + 13.5

= 2 x 26.25 + 13.5

= 52.5 + 13.5

= 66 m²

→ Plastering the given area

Rate of plastering 1 m² = Rs. 8

Cost of plastering 66 m²

= Rs 66 x 8

= Rs 528

Therefore, an amount of rupees 528 must be given to plaster the walls and ceilings of the room of given dimensions.