Math, asked by brainpower889, 18 days ago

please answer my question please​

Attachments:

Answers

Answered by mathdude500
6

Question :-

On his 21st birthday, a boy decided to distribute blankets to the poor instead of giving party to his friends. He bought 8500 blankets to distribute them to old age home, orphanage and road side beggars. The number of blankets distributed to old age home was twice of the blankets distributed to orphanage. Also, 100 more than thrice the number of blankets distributed to orphanage were given to road side beggars.

1. Form an equation to the given condition.

2. Number of blankets distributed to orphanage.

3. Number of blankets distributed to old age home.

4. Number of blankets distributed to road side beggars.

\large\underline{\sf{Solution-}}

Let assume that number of blankets distributed to orphanage be x.

As it is given that, the number of blankets distributed to old age home was twice of the blankets distributed to orphanage.

So, Number of blankets distributed to old age home = 2x

Further given that, Number of blankets distributed to road side beggars is 100 more than thrice the number of blankets distributed to orphanage.

So, Number of blankets distributed to road side beggars = 3x + 100.

So, we have

Number of blankets distributed to orphanage be x.

Number of blankets distributed to old age home = 2x

Number of blankets distributed to road side beggars = 3x + 100.

Total blanket distributed = 8500

Thus,

\rm \: x + 2x + 3x + 100 = 8500 \\

\rm \: 6x = 8500 - 100 \\

\rm \: 6x = 8400 \\

\rm\implies \:x = 1400 \\

Hence,

Number of blankets distributed to orphanage = 1400.

Number of blankets distributed to old age home = 2800

Number of blankets distributed to road side beggars = 3 × 1400 + 100 = 4300

Similar questions