CBSE BOARD X, asked by Prabhakar1230, 8 months ago

Please answer my question plzzzz.

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Answered by Anonymous
0

given,

Focal length(f)= -20

Magnification(m)= -1/5

Object distance(u)= ?

We know

m=-v/u

- 1/5= - v/u

-u= - 5v

u=5v.

Now

1/f=1/v+1/u

-1/20=1/v+1/5v

-1/20=5+1/5v

-1/20=6/5v

-5v=120

-v=120/5

Therefore v=-24

Now putting the value of v in .....i,we get. u=5*-24=-120 cm

Thus the object should be placed at 120 cm in front of the mirror

Answered by prashanthikumarisgt1
0

Answer:24 cm

Explanation:given in the picture

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