please answer my question tennetiraj sir
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Step-by-step explanation:
given : x³+ax²+bx-2b. ( equation 1 )
x - 6, x = 6
a - b = 4
solve, Put the value of x in equation 1
x³+ax²+bx-2b = 0
(6)³+a(6)²+b(6)-2b = 0
216+36a+6b-2b = 0
36a +4b = -216
4(9a+b)= -216
9a + b = -54. [ given, a-b = 4
a = 4+b ]
9(4+b)+b = -54
36 +9b+b = -54
10b = - 18
b = -18/10
b = -9/5
put, the value of b
a = 4 + b
a = 4 -9/5
a = 20 - 9 /5
a = 11/5
Thus, the value of a is 11/5 and b is - 9/5
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