Please answer my question urgently
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Answer:
x = 6
Step-by-step explanation:
Given: (2x - 3) = √2x² - 2x + 21
On squaring both sides, we get
⇒ (2x - 3)² = (√2x² - 2x + 21)²
⇒ 4x² + 9 - 12x = 2x² - 2x + 21
⇒ 2x² - 10x - 12 = 0
⇒ x² - 5x - 6 = 0
⇒ x² - 6x + x - 6 = 0
⇒ x(x - 6) + (x - 6) = 0
⇒ (x + 1)(x - 6) = 0
⇒ x = 6, -1{∴Not satisfies}
⇒ x = 6
Hope it helps!
Answered by
0
Given: (2x - 3) = √2x² - 2x + 21
On squaring both sides, we get
⇒ (2x - 3)² = (√2x² - 2x + 21)²
⇒ 4x² + 9 - 12x = 2x² - 2x + 21
⇒ 2x² - 10x - 12 = 0
⇒ x² - 5x - 6 = 0
⇒ x² - 6x + x - 6 = 0
⇒ x(x - 6) + (x - 6) = 0
⇒ (x + 1)(x - 6) = 0
⇒ x = 6, -1{∴Not satisfies}
⇒ x = 6
Hope it helps!
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