please answer my question urgently properly
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for bit 1
x can be
2 as 4+3+2=9divisible by 3
it can be 5 as 4+3+5=12 divisible by 3
it can be 8 as 4+3+8=15 divisible by 3
x can be
2 as 4+3+2=9divisible by 3
it can be 5 as 4+3+5=12 divisible by 3
it can be 8 as 4+3+8=15 divisible by 3
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Solution. 7)
Since the number is multiple of 3,
So the sum of digits is also a multiple of 3
On putting x = 2
Sum of digits = 3 + 4 + 2 = 9
x= 2
Solution. 8)
Since the number is multiple of 9,
Sum of digits is multiple of 9
On putting x= 0
Sum of digits = 4+ 2+0+3
x= 0
Since the number is multiple of 3,
So the sum of digits is also a multiple of 3
On putting x = 2
Sum of digits = 3 + 4 + 2 = 9
x= 2
Solution. 8)
Since the number is multiple of 9,
Sum of digits is multiple of 9
On putting x= 0
Sum of digits = 4+ 2+0+3
x= 0
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