Math, asked by arpitshukla3, 1 year ago

please answer my question urgently properly

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Answered by Anonymous
0
for bit 1
x can be
2 as 4+3+2=9divisible by 3
it can be 5 as 4+3+5=12 divisible by 3
it can be 8 as 4+3+8=15 divisible by 3
Answered by gaurav2013c
0
Solution. 7)

Since the number is multiple of 3,
So the sum of digits is also a multiple of 3

On putting x = 2
Sum of digits = 3 + 4 + 2 = 9

x= 2

Solution. 8)

Since the number is multiple of 9,
Sum of digits is multiple of 9

On putting x= 0
Sum of digits = 4+ 2+0+3

x= 0
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