Please answer my question with solution or via picture if possible.
pg. 348
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option a) 40 Joule is correct
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saadyasinkhan:
Thank you so much
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where f. =ma
a=f/m
a=2/5;
a=0.4;
now
s=ut+1/2at²
u=0;
s=0+1/2×0.4×(10)²;
s=20;
now
workdone=f×s;
20×2=40;
a=f/m
a=2/5;
a=0.4;
now
s=ut+1/2at²
u=0;
s=0+1/2×0.4×(10)²;
s=20;
now
workdone=f×s;
20×2=40;
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